Class 10 Maths Chapter 1: Real Numbers — Important Questions & Sample Paper
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Reviewed by qpaper's CBSE curriculum team · Edited by Mohit · Updated June 2026
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Yes — this page has 44+ original Class 10 Mathematics Chapter 1 (“Real Numbers”) important questions with answers (Multiple Choice (MCQ), Assertion–Reason, Short Answer, Short Answer, Long Answer, Case Study). Practise them free, or generate a full CBSE board-pattern sample paper (80 marks) and export it to PDF or Word — in English & Hindi, for 2026-27.
Chapter 1 of Class 10 CBSE Mathematics, 'Real Numbers', revisits the number system to build a deeper understanding of rational and irrational numbers. The chapter begins with Euclid's division lemma, a fundamental concept used primarily to compute the Highest Common Factor (HCF) of two positive integers. It then proceeds to the Fundamental Theorem of Arithmetic, which states that every composite number can be uniquely expressed as a product of primes. This theorem forms the backbone of several applications, including finding HCF and Least Common Multiple (LCM) via prime factorisation, and verifying the relationship HCF × LCM = product of the two numbers. A significant portion of the chapter is devoted to irrational numbers, where students learn to prove the irrationality of numbers like √2, √3, and their combinations (e.g., 3+2√5). The decimal expansions of rational numbers are explored, with clear conditions for terminating and non‑terminating repeating decimals. Typical exam questions include proving irrationality, determining after how many decimal places a rational number terminates, word problems on HCF and LCM (such as packing items or arranging objects), and proofs involving properties of integers. Mastering this chapter not only builds algebraic reasoning but also enhances problem‑solving skills critical for higher mathematics.
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Mathematics — Real Numbers
SECTION A
- 1.1
Two numbers are in the ratio 3:4 and their LCM is 72. The sum of the numbers is:
(a) 42(b) 36(c) 84(d) 21 - 2.1
Which of the following rational numbers has a non-terminating repeating decimal expansion?
(a) 7/50(b) 11/25(c) 33/120(d) 53/240 - 3.1
If p is a prime number, then √p is:
(a) always rational(b) always irrational(c) rational only if p=2(d) sometimes rational
+ 41 more questions in the full paper
Generate full paperMarks distribution & blueprint
In a CBSE exam, this chapter typically contributes questions across the following types. The last column shows how many original questions of each type we have ready in our bank for this chapter:
| Question type | Marks each | In our bank |
|---|---|---|
| Multiple Choice (MCQ) | 1 mark | 13 |
| Assertion–Reason | 1 mark | 6 |
| Short Answer | 2 marks | 8 |
| Short Answer | 3 marks | 6 |
| Long Answer | 5 marks | 5 |
| Case Study | 4 marks | 6 |
44 original, exam-style questions in our bank for this chapter — with answers.
Important & sample questions (with answers)
Real, exam-style questions to practise and revise — each with its answer. Generate a full paper for unlimited more.
- Multiple Choice (MCQ)
Q1. Two numbers are in the ratio 3:4 and their LCM is 72. The sum of the numbers is:
1 mark(A) 42(B) 36(C) 84(D) 21▸ Answer▾ Answer
42
- Multiple Choice (MCQ)
Q2. Which of the following rational numbers has a non-terminating repeating decimal expansion?
1 mark(A) 7/50(B) 11/25(C) 33/120(D) 53/240▸ Answer▾ Answer
53/240
- Multiple Choice (MCQ)
Q3. If p is a prime number, then √p is:
1 mark(A) always rational(B) always irrational(C) rational only if p=2(D) sometimes rational▸ Answer▾ Answer
always irrational
- Multiple Choice (MCQ)
Q4. The HCF of 405 and 2520 is:
1 mark(A) 45(B) 60(C) 75(D) 90▸ Answer▾ Answer
45
- Assertion–Reason
Q5. Assertion (A): The number 5 - √3 is irrational. Reason (R): The difference of a rational number and an irrational number is an irrational number.
1 mark(A) Both A and R are true and R is the correct explanation of A.(B) Both A and R are true but R is not the correct explanation of A.(C) A is true but R is false.(D) A is false but R is true.▸ Answer▾ Answer
Both A and R are true and R is the correct explanation of A.
- Short Answer
Q6. Prove that √5 is irrational.
2 marks▸ Answer▾ Answer
√5 is irrational.
- Short Answer
Q7. Prove that the square of any positive integer is of the form 5q, 5q+1, or 5q+4, for some integer q.
2 marks▸ Answer▾ Answer
The square of any positive integer is of the form 5q, 5q+1, or 5q+4.
- Short Answer
Q8. Prove that √3 is irrational.
3 marks▸ Answer▾ Answer
√3 is irrational.
- Short Answer
Q9. Prove that one and only one out of n, n+2, n+4 is divisible by 3, where n is any positive integer.
3 marks▸ Answer▾ Answer
Exactly one of n, n+2, n+4 is divisible by 3.
- Long Answer
Q10. Show that the square of any positive integer cannot be expressed in the form 5q + 2 or 5q + 3, where q is an integer.
5 marks▸ Answer▾ Answer
The square is always of the form 5q, 5q+1, or 5q+4, never 5q+2 or 5q+3.
- Long Answer
Q11. Prove that √2 + √3 is an irrational number.
5 marks▸ Answer▾ Answer
Therefore, √2 + √3 is irrational.
- Case Study
Q12. Sara is checking whether certain rational numbers have terminating decimal expansions. She knows that a reduced fraction a/b has a terminating decimal if and only if b has no prime factors other than 2 and 5. She considers the number 27/400.
4 marks- (i) Express 400 as a product of its prime factors.2 marks
- (ii) Does 27/400 have a terminating decimal expansion? Justify your answer.2 marks
▸ Answer▾ Answer
Prime factorization: 400 = 2^4 × 5^2. The fraction 27/400 terminates because its denominator has only 2 and 5 as prime factors.
Frequently asked questions
What is the condition for a rational number to have a terminating decimal expansion?
A rational number p/q (in lowest terms) has a terminating decimal expansion if the prime factorisation of q is of the form 2ⁿ5ᵐ, where n and m are non‑negative integers.
How is the irrationality of numbers like 3+2√5 proven?
Assume contrary that 3+2√5 is rational, say equal to a/b. Then √5 = (a/b − 3)/2, making √5 rational, which contradicts the known fact that √5 is irrational. Hence, 3+2√5 is irrational.
What is the relationship between HCF, LCM, and the product of two numbers?
For any two positive integers a and b, the product of their HCF and LCM equals the product of the numbers: HCF(a,b) × LCM(a,b) = a × b. This is useful for verification and solving problems.
How can prime factorisation be used to find HCF and LCM?
For HCF, take the product of the smallest powers of all common prime factors. For LCM, take the product of the greatest powers of all prime factors appearing in the numbers. This method is efficient and illustrative of the Fundamental Theorem of Arithmetic.
More chapters
- Ch 1: Real Numbers
- Ch 2: Polynomials
- Ch 3: Pair of Linear Equations in Two Variables
- Ch 4: Quadratic Equations
- Ch 5: Arithmetic Progressions
- Ch 6: Triangles
- Ch 7: Coordinate Geometry
- Ch 8: Introduction to Trigonometry
- Ch 9: Some Applications of Trigonometry
- Ch 10: Circles
- Ch 11: Areas Related to Circles
- Ch 12: Surface Areas and Volumes
- Ch 13: Statistics
- Ch 14: Probability